4[4x-3(x+4)]=3+x-(x-3)

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Solution for 4[4x-3(x+4)]=3+x-(x-3) equation:


Simplifying
4[4x + -3(x + 4)] = 3 + x + -1(x + -3)

Reorder the terms:
4[4x + -3(4 + x)] = 3 + x + -1(x + -3)
4[4x + (4 * -3 + x * -3)] = 3 + x + -1(x + -3)
4[4x + (-12 + -3x)] = 3 + x + -1(x + -3)

Reorder the terms:
4[-12 + 4x + -3x] = 3 + x + -1(x + -3)

Combine like terms: 4x + -3x = 1x
4[-12 + 1x] = 3 + x + -1(x + -3)
[-12 * 4 + 1x * 4] = 3 + x + -1(x + -3)
[-48 + 4x] = 3 + x + -1(x + -3)

Reorder the terms:
-48 + 4x = 3 + x + -1(-3 + x)
-48 + 4x = 3 + x + (-3 * -1 + x * -1)
-48 + 4x = 3 + x + (3 + -1x)

Reorder the terms:
-48 + 4x = 3 + 3 + x + -1x

Combine like terms: 3 + 3 = 6
-48 + 4x = 6 + x + -1x

Combine like terms: x + -1x = 0
-48 + 4x = 6 + 0
-48 + 4x = 6

Solving
-48 + 4x = 6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '48' to each side of the equation.
-48 + 48 + 4x = 6 + 48

Combine like terms: -48 + 48 = 0
0 + 4x = 6 + 48
4x = 6 + 48

Combine like terms: 6 + 48 = 54
4x = 54

Divide each side by '4'.
x = 13.5

Simplifying
x = 13.5

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